1x+(2/3)x=24

Solution for 1x+(2/3)x=24 equation:

1x+(2/3)x=24

We move all terms to the left:

1x+(2/3)x-(24)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1x+(+2/3)x-24=0

We add all the numbers together, and all the variables

x+(+2/3)x-24=0

We multiply parentheses

2x^2+x-24=0

a = 2; b = 1; c = -24;
Δ = b2-4ac
Δ = 12-4·2·(-24)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{193}}{2*2}=\frac{-1-\sqrt{193}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{193}}{2*2}=\frac{-1+\sqrt{193}}{4}
$