5(x+3)-7=-2(x+4)+6

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Solution for 5(x+3)-7=-2(x+4)+6 equation: 



5(x+3)-7=-2(x+4)+6

We move all terms to the left:

5(x+3)-7-(-2(x+4)+6)=0

We multiply parentheses

5x-(-2(x+4)+6)+15-7=0



We calculate terms in parentheses: -(-2(x+4)+6), so:

-2(x+4)+6

We multiply parentheses

-2x-8+6

We add all the numbers together, and all the variables

-2x-2

Back to the equation:

-(-2x-2)



We add all the numbers together, and all the variables

5x-(-2x-2)+8=0

We get rid of parentheses

5x+2x+2+8=0

We add all the numbers together, and all the variables

7x+10=0

We move all terms containing x to the left, all other terms to the right

7x=-10

x=-10/7

x=-1+3/7

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