1x+2/3x=24

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Solution for 1x+2/3x=24 equation:



1x+2/3x=24
We move all terms to the left:
1x+2/3x-(24)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
x+2/3x-24=0
We multiply all the terms by the denominator
x*3x-24*3x+2=0
Wy multiply elements
3x^2-72x+2=0
a = 3; b = -72; c = +2;
Δ = b2-4ac
Δ = -722-4·3·2
Δ = 5160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5160}=\sqrt{4*1290}=\sqrt{4}*\sqrt{1290}=2\sqrt{1290}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-2\sqrt{1290}}{2*3}=\frac{72-2\sqrt{1290}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+2\sqrt{1290}}{2*3}=\frac{72+2\sqrt{1290}}{6} $

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