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1=1/2(8a+2)
We move all terms to the left:
1-(1/2(8a+2))=0
Domain of the equation: 2(8a+2))!=0We multiply all the terms by the denominator
a∈R
-(1+1*2(8a+2))=0
We calculate terms in parentheses: -(1+1*2(8a+2)), so:We add all the numbers together, and all the variables
1+1*2(8a+2)
determiningTheFunctionDomain 1*2(8a+2)+1
Wy multiply elements
2a(8+1
Back to the equation:
-(2a(8+1)
-(2a9=0
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