2(3x+7)+3(4x+1)=11(2x-8)

Solution for 2(3x+7)+3(4x+1)=11(2x-8) equation:

2(3x+7)+3(4x+1)=11(2x-8)

We move all terms to the left:

2(3x+7)+3(4x+1)-(11(2x-8))=0

We multiply parentheses

6x+12x-(11(2x-8))+14+3=0


We calculate terms in parentheses: -(11(2x-8)), so:

11(2x-8)

We multiply parentheses

22x-88

Back to the equation:

-(22x-88)


We add all the numbers together, and all the variables

18x-(22x-88)+17=0

We get rid of parentheses

18x-22x+88+17=0

We add all the numbers together, and all the variables

-4x+105=0

We move all terms containing x to the left, all other terms to the right

-4x=-105

x=-105/-4

x=26+1/4