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(T)=-6+3(T-1
We move all terms to the left:
(T)-(-6+3(T-1)=0
We calculate terms in parentheses: -(-6+3(T-1), so:We add all the numbers together, and all the variables
-6+3(T-1
determiningTheFunctionDomain 3(T-1-6
Back to the equation:
-(3(T-1-6)
T-(3(T-7)=0
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| 4(5x-3)=9(2x+4) | | 3x−9=8x+1 | | -6x+2=-x+17 | | N(n)=24-5n | | 2x-(3x-4)=8x+10-6x | | 3(-2n=9)=-15 | | 2x-14(1/7x+3)=-42 | | 5(a+1)-4=9 | | 3/4(8q-12)=15 | | x2+23=56 | | 2x+5=5(x-2)-3x+5 | | 8(x-3)=6x-13 | | 2x-3=-5x-9 | | 3x-7+5x+2=4(2x-3)+11 | | 24=t/4.5 | | 7x-24=5x+4 | | 3/4(8a-12)=15 | | 2.5+2x=7.5+x | | 20=m÷4 | | X^2+y=64 | | -10x-(-35)+24=89 | | 3x+95+25=180 | | 6x-3(-2x+8)=-132 | | 100+60x=180 | | 11x-16=4x+19 | | 4x^2+2x-10=9x-9 | | -7x+43=180 | | -3x-4(6x+9)=180 | | 5/2x+31x=38 | | 21+9j-10=(-277) | | 4/7t=24 | | Y=40*40x |