19x-28=4(3x-5)+7x-8

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Solution for 19x-28=4(3x-5)+7x-8 equation: 



19x-28=4(3x-5)+7x-8

We move all terms to the left:

19x-28-(4(3x-5)+7x-8)=0



We calculate terms in parentheses: -(4(3x-5)+7x-8), so:

4(3x-5)+7x-8

We add all the numbers together, and all the variables

7x+4(3x-5)-8

We multiply parentheses

7x+12x-20-8

We add all the numbers together, and all the variables

19x-28

Back to the equation:

-(19x-28)



We get rid of parentheses

19x-19x+28-28=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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