(((2x-7)/5)+11)=4

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Solution for (((2x-7)/5)+11)=4 equation: 



(((2x-7)/5)+11)=4

We move all terms to the left:

(((2x-7)/5)+11)-(4)=0

We multiply all the terms by the denominator


(((2x-7)-4*5)+11)=0



We calculate terms in parentheses: +(((2x-7)-4*5)+11), so:

((2x-7)-4*5)+11



We calculate terms in parentheses: +((2x-7)-4*5), so:

(2x-7)-4*5

We add all the numbers together, and all the variables

(2x-7)-20

We get rid of parentheses

2x-7-20

We add all the numbers together, and all the variables

2x-27

Back to the equation:

+(2x-27)



We get rid of parentheses

2x-27+11

We add all the numbers together, and all the variables

2x-16

Back to the equation:

+(2x-16)



We get rid of parentheses

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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