-4(2t-2)+6t=4t-3

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Solution for -4(2t-2)+6t=4t-3 equation: 



-4(2t-2)+6t=4t-3

We move all terms to the left:

-4(2t-2)+6t-(4t-3)=0

We add all the numbers together, and all the variables

6t-4(2t-2)-(4t-3)=0

We multiply parentheses

6t-8t-(4t-3)+8=0

We get rid of parentheses

6t-8t-4t+3+8=0

We add all the numbers together, and all the variables

-6t+11=0

We move all terms containing t to the left, all other terms to the right

-6t=-11

t=-11/-6

t=1+5/6

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