19=4(n+2)+3

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Solution for 19=4(n+2)+3 equation: 



19=4(n+2)+3

We move all terms to the left:

19-(4(n+2)+3)=0



We calculate terms in parentheses: -(4(n+2)+3), so:

4(n+2)+3

We multiply parentheses

4n+8+3

We add all the numbers together, and all the variables

4n+11

Back to the equation:

-(4n+11)



We get rid of parentheses

-4n-11+19=0

We add all the numbers together, and all the variables

-4n+8=0

We move all terms containing n to the left, all other terms to the right

-4n=-8

n=-8/-4

n=+2

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