8+1=3-3(x+3)+4x

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Solution for 8+1=3-3(x+3)+4x equation: 



8+1=3-3(x+3)+4x

We move all terms to the left:

8+1-(3-3(x+3)+4x)=0

We add all the numbers together, and all the variables

-(3-3(x+3)+4x)+9=0



We calculate terms in parentheses: -(3-3(x+3)+4x), so:

3-3(x+3)+4x

determiningTheFunctionDomain
-3(x+3)+4x+3

We add all the numbers together, and all the variables

4x-3(x+3)+3

We multiply parentheses

4x-3x-9+3

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We get rid of parentheses

-x+6+9=0

We add all the numbers together, and all the variables

-1x+15=0

We move all terms containing x to the left, all other terms to the right

-x=-15

x=-15/-1

x=+15

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