(7/4)x-3=2+(9/2)x

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Solution for (7/4)x-3=2+(9/2)x equation:



(7/4)x-3=2+(9/2)x
We move all terms to the left:
(7/4)x-3-(2+(9/2)x)=0
Domain of the equation: 4)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2)x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+7/4)x-(2+(+9/2)x)-3=0
We multiply parentheses
7x^2-(2+(+9/2)x)-3=0
We multiply all the terms by the denominator
7x^2*2)x)-(2+(-3*2)x)+9=0
We add all the numbers together, and all the variables
7x^2*2)x)-(2+(-6)x)+9=0
Wy multiply elements
14x^3-6)x)+9=0
We do not support expression: x^3

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