19=2(x-3)+5

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Solution for 19=2(x-3)+5 equation: 



19=2(x-3)+5

We move all terms to the left:

19-(2(x-3)+5)=0



We calculate terms in parentheses: -(2(x-3)+5), so:

2(x-3)+5

We multiply parentheses

2x-6+5

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We get rid of parentheses

-2x+1+19=0

We add all the numbers together, and all the variables

-2x+20=0

We move all terms containing x to the left, all other terms to the right

-2x=-20

x=-20/-2

x=+10

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