126=(3w+3)(w)

Solution for 126=(3w+3)(w) equation:

126=(3w+3)(w)

We move all terms to the left:

126-((3w+3)(w))=0


We calculate terms in parentheses: -((3w+3)w), so:

(3w+3)w

We multiply parentheses

3w^2+3w

Back to the equation:

-(3w^2+3w)


We get rid of parentheses

-3w^2-3w+126=0

a = -3; b = -3; c = +126;
Δ = b2-4ac
Δ = -32-4·(-3)·126
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-39}{2*-3}=\frac{-36}{-6}
=+6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+39}{2*-3}=\frac{42}{-6}
=-7
$