2(r-3)+3(2r+1)=4(2r+3)+3(r-13)

Solution for 2(r-3)+3(2r+1)=4(2r+3)+3(r-13) equation:

2(r-3)+3(2r+1)=4(2r+3)+3(r-13)

We move all terms to the left:

2(r-3)+3(2r+1)-(4(2r+3)+3(r-13))=0

We multiply parentheses

2r+6r-(4(2r+3)+3(r-13))-6+3=0


We calculate terms in parentheses: -(4(2r+3)+3(r-13)), so:

4(2r+3)+3(r-13)

We multiply parentheses

8r+3r+12-39

We add all the numbers together, and all the variables

11r-27

Back to the equation:

-(11r-27)


We add all the numbers together, and all the variables

8r-(11r-27)-3=0

We get rid of parentheses

8r-11r+27-3=0

We add all the numbers together, and all the variables

-3r+24=0

We move all terms containing r to the left, all other terms to the right

-3r=-24

r=-24/-3

r=+8