19=2(c+1)+7

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Solution for 19=2(c+1)+7 equation: 



19=2(c+1)+7

We move all terms to the left:

19-(2(c+1)+7)=0



We calculate terms in parentheses: -(2(c+1)+7), so:

2(c+1)+7

We multiply parentheses

2c+2+7

We add all the numbers together, and all the variables

2c+9

Back to the equation:

-(2c+9)



We get rid of parentheses

-2c-9+19=0

We add all the numbers together, and all the variables

-2c+10=0

We move all terms containing c to the left, all other terms to the right

-2c=-10

c=-10/-2

c=+5

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