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(10x+2)(6x+4)=
We move all terms to the left:
(10x+2)(6x+4)-()=0
We add all the numbers together, and all the variables
(10x+2)(6x+4)=0
We multiply parentheses ..
(+60x^2+40x+12x+8)=0
We get rid of parentheses
60x^2+40x+12x+8=0
We add all the numbers together, and all the variables
60x^2+52x+8=0
a = 60; b = 52; c = +8;
Δ = b2-4ac
Δ = 522-4·60·8
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-28}{2*60}=\frac{-80}{120} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+28}{2*60}=\frac{-24}{120} =-1/5 $
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