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196=4x(x-7)
We move all terms to the left:
196-(4x(x-7))=0
We calculate terms in parentheses: -(4x(x-7)), so:We get rid of parentheses
4x(x-7)
We multiply parentheses
4x^2-28x
Back to the equation:
-(4x^2-28x)
-4x^2+28x+196=0
a = -4; b = 28; c = +196;
Δ = b2-4ac
Δ = 282-4·(-4)·196
Δ = 3920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3920}=\sqrt{784*5}=\sqrt{784}*\sqrt{5}=28\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28\sqrt{5}}{2*-4}=\frac{-28-28\sqrt{5}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28\sqrt{5}}{2*-4}=\frac{-28+28\sqrt{5}}{-8} $
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