3(k+1)+24=2(1-k)

Solution for 3(k+1)+24=2(1-k) equation:

3(k+1)+24=2(1-k)

We move all terms to the left:

3(k+1)+24-(2(1-k))=0

We add all the numbers together, and all the variables

3(k+1)-(2(-1k+1))+24=0

We multiply parentheses

3k-(2(-1k+1))+3+24=0


We calculate terms in parentheses: -(2(-1k+1)), so:

2(-1k+1)

We multiply parentheses

-2k+2

Back to the equation:

-(-2k+2)


We add all the numbers together, and all the variables

3k-(-2k+2)+27=0

We get rid of parentheses

3k+2k-2+27=0

We add all the numbers together, and all the variables

5k+25=0

We move all terms containing k to the left, all other terms to the right

5k=-25

k=-25/5

k=-5