2(3y-1)+3(2y+1)=5(y+3)

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Solution for 2(3y-1)+3(2y+1)=5(y+3) equation: 



2(3y-1)+3(2y+1)=5(y+3)

We move all terms to the left:

2(3y-1)+3(2y+1)-(5(y+3))=0

We multiply parentheses

6y+6y-(5(y+3))-2+3=0



We calculate terms in parentheses: -(5(y+3)), so:

5(y+3)

We multiply parentheses

5y+15

Back to the equation:

-(5y+15)



We add all the numbers together, and all the variables

12y-(5y+15)+1=0

We get rid of parentheses

12y-5y-15+1=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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