19/2x=-57/10x+152

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Solution for 19/2x=-57/10x+152 equation:



19/2x=-57/10x+152
We move all terms to the left:
19/2x-(-57/10x+152)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 10x+152)!=0
x∈R
We get rid of parentheses
19/2x+57/10x-152=0
We calculate fractions
190x/20x^2+114x/20x^2-152=0
We multiply all the terms by the denominator
190x+114x-152*20x^2=0
We add all the numbers together, and all the variables
304x-152*20x^2=0
Wy multiply elements
-3040x^2+304x=0
a = -3040; b = 304; c = 0;
Δ = b2-4ac
Δ = 3042-4·(-3040)·0
Δ = 92416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{92416}=304$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(304)-304}{2*-3040}=\frac{-608}{-6080} =1/10 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(304)+304}{2*-3040}=\frac{0}{-6080} =0 $

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