5(1y+2)=1/2(10y+20)

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Solution for 5(1y+2)=1/2(10y+20) equation: 



5(1y+2)=1/2(10y+20)

We move all terms to the left:

5(1y+2)-(1/2(10y+20))=0



Domain of the equation: 2(10y+20))!=0

y∈R



We add all the numbers together, and all the variables

5(y+2)-(1/2(10y+20))=0

We multiply parentheses

5y-(1/2(10y+20))+10=0

We multiply all the terms by the denominator


5y*2(10y+20))-(1+10*2(10y+20))=0

Wy multiply elements

10y^2(1+20y(1=0

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