19-2x+5x-28=6+1/2x

Solution for 19-2x+5x-28=6+1/2x equation:

19-2x+5x-28=6+1/2x

We move all terms to the left:

19-2x+5x-28-(6+1/2x)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-2x+5x-(1/2x+6)+19-28=0

We add all the numbers together, and all the variables

3x-(1/2x+6)-9=0

We get rid of parentheses

3x-1/2x-6-9=0

We multiply all the terms by the denominator


3x*2x-6*2x-9*2x-1=0

Wy multiply elements

6x^2-12x-18x-1=0

We add all the numbers together, and all the variables

6x^2-30x-1=0

a = 6; b = -30; c = -1;
Δ = b2-4ac
Δ = -302-4·6·(-1)
Δ = 924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{924}=\sqrt{4*231}=\sqrt{4}*\sqrt{231}=2\sqrt{231}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{231}}{2*6}=\frac{30-2\sqrt{231}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{231}}{2*6}=\frac{30+2\sqrt{231}}{12}
$