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5x+4((32-4x)/5)=31
We move all terms to the left:
5x+4((32-4x)/5)-(31)=0
We add all the numbers together, and all the variables
5x+4((-4x+32)/5)-31=0
We multiply all the terms by the denominator
5x*5)+4((-4x+32)-31*5)=0
We add all the numbers together, and all the variables
5x*5)+4((-4x+32)=0
Wy multiply elements
25x^2=0
a = 25; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·25·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{50}=0$
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