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18=4x^2
We move all terms to the left:
18-(4x^2)=0
a = -4; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·(-4)·18
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{2}}{2*-4}=\frac{0-12\sqrt{2}}{-8} =-\frac{12\sqrt{2}}{-8} =-\frac{3\sqrt{2}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{2}}{2*-4}=\frac{0+12\sqrt{2}}{-8} =\frac{12\sqrt{2}}{-8} =\frac{3\sqrt{2}}{-2} $
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