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7x^2-28x=147
We move all terms to the left:
7x^2-28x-(147)=0
a = 7; b = -28; c = -147;
Δ = b2-4ac
Δ = -282-4·7·(-147)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-70}{2*7}=\frac{-42}{14} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+70}{2*7}=\frac{98}{14} =7 $
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