-4(6+4a)=4a+6(-12-4a)

Solution for -4(6+4a)=4a+6(-12-4a) equation:

-4(6+4a)=4a+6(-12-4a)

We move all terms to the left:

-4(6+4a)-(4a+6(-12-4a))=0

We add all the numbers together, and all the variables

-4(4a+6)-(4a+6(-4a-12))=0

We multiply parentheses

-16a-(4a+6(-4a-12))-24=0


We calculate terms in parentheses: -(4a+6(-4a-12)), so:

4a+6(-4a-12)

We multiply parentheses

4a-24a-72

We add all the numbers together, and all the variables

-20a-72

Back to the equation:

-(-20a-72)


We get rid of parentheses

-16a+20a+72-24=0

We add all the numbers together, and all the variables

4a+48=0

We move all terms containing a to the left, all other terms to the right

4a=-48

a=-48/4

a=-12