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180=x+1/3x+x-93
We move all terms to the left:
180-(x+1/3x+x-93)=0
Domain of the equation: 3x+x-93)!=0We add all the numbers together, and all the variables
x∈R
-(2x+1/3x-93)+180=0
We get rid of parentheses
-2x-1/3x+93+180=0
We multiply all the terms by the denominator
-2x*3x+93*3x+180*3x-1=0
Wy multiply elements
-6x^2+279x+540x-1=0
We add all the numbers together, and all the variables
-6x^2+819x-1=0
a = -6; b = 819; c = -1;
Δ = b2-4ac
Δ = 8192-4·(-6)·(-1)
Δ = 670737
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(819)-\sqrt{670737}}{2*-6}=\frac{-819-\sqrt{670737}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(819)+\sqrt{670737}}{2*-6}=\frac{-819+\sqrt{670737}}{-12} $
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