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-1/2x+10+1=3/x+5
We move all terms to the left:
-1/2x+10+1-(3/x+5)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x+5)!=0We add all the numbers together, and all the variables
x∈R
-1/2x-(3/x+5)+11=0
We get rid of parentheses
-1/2x-3/x-5+11=0
We calculate fractions
(-x)/2x^2+(-6x)/2x^2-5+11=0
We add all the numbers together, and all the variables
(-1x)/2x^2+(-6x)/2x^2-5+11=0
We add all the numbers together, and all the variables
(-1x)/2x^2+(-6x)/2x^2+6=0
We multiply all the terms by the denominator
(-1x)+(-6x)+6*2x^2=0
Wy multiply elements
12x^2+(-1x)+(-6x)=0
We get rid of parentheses
12x^2-1x-6x=0
We add all the numbers together, and all the variables
12x^2-7x=0
a = 12; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·12·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*12}=\frac{14}{24} =7/12 $
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