4(3x-5)-2=4(x-4)+58

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Solution for 4(3x-5)-2=4(x-4)+58 equation: 



4(3x-5)-2=4(x-4)+58

We move all terms to the left:

4(3x-5)-2-(4(x-4)+58)=0

We multiply parentheses

12x-(4(x-4)+58)-20-2=0



We calculate terms in parentheses: -(4(x-4)+58), so:

4(x-4)+58

We multiply parentheses

4x-16+58

We add all the numbers together, and all the variables

4x+42

Back to the equation:

-(4x+42)



We add all the numbers together, and all the variables

12x-(4x+42)-22=0

We get rid of parentheses

12x-4x-42-22=0

We add all the numbers together, and all the variables

8x-64=0

We move all terms containing x to the left, all other terms to the right

8x=64

x=64/8

x=8

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