C-4(x-3)+7=6-(x-4)

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Solution for C-4(x-3)+7=6-(x-4) equation:



-4(C-3)+7=6-(C-4)
We move all terms to the left:
-4(C-3)+7-(6-(C-4))=0
We multiply parentheses
-4C-(6-(C-4))+12+7=0
We calculate terms in parentheses: -(6-(C-4)), so:
6-(C-4)
determiningTheFunctionDomain -(C-4)+6
We get rid of parentheses
-C+4+6
We add all the numbers together, and all the variables
-1C+10
Back to the equation:
-(-1C+10)
We add all the numbers together, and all the variables
-4C-(-1C+10)+19=0
We get rid of parentheses
-4C+1C-10+19=0
We add all the numbers together, and all the variables
-3C+9=0
We move all terms containing C to the left, all other terms to the right
-3C=-9
C=-9/-3
C=+3

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