180=x+(x2+6)

Solution for 180=x+(x2+6) equation:

180=x+(x2+6)

We move all terms to the left:

180-(x+(x2+6))=0

We add all the numbers together, and all the variables

-(x+(+x^2+6))+180=0


We calculate terms in parentheses: -(x+(+x^2+6)), so:

x+(+x^2+6)

determiningTheFunctionDomain
(+x^2+6)+x

We get rid of parentheses

x^2+x+6

Back to the equation:

-(x^2+x+6)


We get rid of parentheses

-x^2-x-6+180=0

We add all the numbers together, and all the variables

-1x^2-1x+174=0

a = -1; b = -1; c = +174;
Δ = b2-4ac
Δ = -12-4·(-1)·174
Δ = 697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{697}}{2*-1}=\frac{1-\sqrt{697}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{697}}{2*-1}=\frac{1+\sqrt{697}}{-2}
$