180=(x2+3)+x

Solution for 180=(x2+3)+x equation:

180=(x2+3)+x

We move all terms to the left:

180-((x2+3)+x)=0

We add all the numbers together, and all the variables

-((+x^2+3)+x)+180=0


We calculate terms in parentheses: -((+x^2+3)+x), so:

(+x^2+3)+x

We get rid of parentheses

x^2+x+3

Back to the equation:

-(x^2+x+3)


We get rid of parentheses

-x^2-x-3+180=0

We add all the numbers together, and all the variables

-1x^2-1x+177=0

a = -1; b = -1; c = +177;
Δ = b2-4ac
Δ = -12-4·(-1)·177
Δ = 709
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{709}}{2*-1}=\frac{1-\sqrt{709}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{709}}{2*-1}=\frac{1+\sqrt{709}}{-2}
$