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(3x+10)=(2x+-40)
We move all terms to the left:
(3x+10)-((2x+-40))=0
We add all the numbers together, and all the variables
(3x+10)-((2x-40))=0
We get rid of parentheses
3x-((2x-40))+10=0
We calculate terms in parentheses: -((2x-40)), so:We get rid of parentheses
(2x-40)
We get rid of parentheses
2x-40
Back to the equation:
-(2x-40)
3x-2x+40+10=0
We add all the numbers together, and all the variables
x+50=0
We move all terms containing x to the left, all other terms to the right
x=-50
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