180=x+(1/2x)+(x-5)

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Solution for 180=x+(1/2x)+(x-5) equation: 



180=x+(1/2x)+(x-5)

We move all terms to the left:

180-(x+(1/2x)+(x-5))=0



Domain of the equation: 2x)+(x-5))!=0

x∈R



We add all the numbers together, and all the variables

-(x+(+1/2x)+(x-5))+180=0

We multiply all the terms by the denominator


-(x+(+1+180*2x)+(x-5))=0



We calculate terms in parentheses: -(x+(+1+180*2x)+(x-5)), so:

x+(+1+180*2x)+(x-5)

We add all the numbers together, and all the variables

x+(180*2x+1)+(x-5)

We get rid of parentheses

x+180*2x+x+1-5

We add all the numbers together, and all the variables

2x+180*2x-4

Wy multiply elements

2x+360x-4

We add all the numbers together, and all the variables

362x-4

Back to the equation:

-(362x-4)



We get rid of parentheses

-362x+4=0

We move all terms containing x to the left, all other terms to the right

-362x=-4

x=-4/-362

x=2/181

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