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10(x+2)=5(x+4)
We move all terms to the left:
10(x+2)-(5(x+4))=0
We multiply parentheses
10x-(5(x+4))+20=0
We calculate terms in parentheses: -(5(x+4)), so:We get rid of parentheses
5(x+4)
We multiply parentheses
5x+20
Back to the equation:
-(5x+20)
10x-5x-20+20=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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