3(7-9k)+23k=4k-(24+k)

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Solution for 3(7-9k)+23k=4k-(24+k) equation: 



3(7-9k)+23k=4k-(24+k)

We move all terms to the left:

3(7-9k)+23k-(4k-(24+k))=0

We add all the numbers together, and all the variables

3(-9k+7)+23k-(4k-(k+24))=0

We add all the numbers together, and all the variables

23k+3(-9k+7)-(4k-(k+24))=0

We multiply parentheses

23k-27k-(4k-(k+24))+21=0



We calculate terms in parentheses: -(4k-(k+24)), so:

4k-(k+24)

We get rid of parentheses

4k-k-24

We add all the numbers together, and all the variables

3k-24

Back to the equation:

-(3k-24)



We add all the numbers together, and all the variables

-4k-(3k-24)+21=0

We get rid of parentheses

-4k-3k+24+21=0

We add all the numbers together, and all the variables

-7k+45=0

We move all terms containing k to the left, all other terms to the right

-7k=-45

k=-45/-7

k=6+3/7

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