-4(2u-4)+2u=2(u+3)

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Solution for -4(2u-4)+2u=2(u+3) equation: 



-4(2u-4)+2u=2(u+3)

We move all terms to the left:

-4(2u-4)+2u-(2(u+3))=0

We add all the numbers together, and all the variables

2u-4(2u-4)-(2(u+3))=0

We multiply parentheses

2u-8u-(2(u+3))+16=0



We calculate terms in parentheses: -(2(u+3)), so:

2(u+3)

We multiply parentheses

2u+6

Back to the equation:

-(2u+6)



We add all the numbers together, and all the variables

-6u-(2u+6)+16=0

We get rid of parentheses

-6u-2u-6+16=0

We add all the numbers together, and all the variables

-8u+10=0

We move all terms containing u to the left, all other terms to the right

-8u=-10

u=-10/-8

u=1+1/4

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