180=(x+6)+(3x-78)+(x-2)

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Solution for 180=(x+6)+(3x-78)+(x-2) equation: 



180=(x+6)+(3x-78)+(x-2)

We move all terms to the left:

180-((x+6)+(3x-78)+(x-2))=0



We calculate terms in parentheses: -((x+6)+(3x-78)+(x-2)), so:

(x+6)+(3x-78)+(x-2)

We get rid of parentheses

x+3x+x+6-78-2

We add all the numbers together, and all the variables

5x-74

Back to the equation:

-(5x-74)



We get rid of parentheses

-5x+74+180=0

We add all the numbers together, and all the variables

-5x+254=0

We move all terms containing x to the left, all other terms to the right

-5x=-254

x=-254/-5

x=50+4/5

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