3(m+4)-6m=2(4-2m)

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Solution for 3(m+4)-6m=2(4-2m) equation: 



3(m+4)-6m=2(4-2m)

We move all terms to the left:

3(m+4)-6m-(2(4-2m))=0

We add all the numbers together, and all the variables

3(m+4)-6m-(2(-2m+4))=0

We add all the numbers together, and all the variables

-6m+3(m+4)-(2(-2m+4))=0

We multiply parentheses

-6m+3m-(2(-2m+4))+12=0



We calculate terms in parentheses: -(2(-2m+4)), so:

2(-2m+4)

We multiply parentheses

-4m+8

Back to the equation:

-(-4m+8)



We add all the numbers together, and all the variables

-3m-(-4m+8)+12=0

We get rid of parentheses

-3m+4m-8+12=0

We add all the numbers together, and all the variables

m+4=0

We move all terms containing m to the left, all other terms to the right

m=-4

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