3(f+19)=12

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Solution for 3(f+19)=12 equation: 



3(f+19)=12

We move all terms to the left:

3(f+19)-(12)=0

We multiply parentheses

3f+57-12=0

We add all the numbers together, and all the variables

3f+45=0

We move all terms containing f to the left, all other terms to the right

3f=-45

f=-45/3

f=-15

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