180=(7x-2)+(2x+22)+3x

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Solution for 180=(7x-2)+(2x+22)+3x equation: 



180=(7x-2)+(2x+22)+3x

We move all terms to the left:

180-((7x-2)+(2x+22)+3x)=0



We calculate terms in parentheses: -((7x-2)+(2x+22)+3x), so:

(7x-2)+(2x+22)+3x

We add all the numbers together, and all the variables

3x+(7x-2)+(2x+22)

We get rid of parentheses

3x+7x+2x-2+22

We add all the numbers together, and all the variables

12x+20

Back to the equation:

-(12x+20)



We get rid of parentheses

-12x-20+180=0

We add all the numbers together, and all the variables

-12x+160=0

We move all terms containing x to the left, all other terms to the right

-12x=-160

x=-160/-12

x=13+1/3

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