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4/5x+6/10x=14
We move all terms to the left:
4/5x+6/10x-(14)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x!=0We calculate fractions
x!=0/10
x!=0
x∈R
40x/50x^2+30x/50x^2-14=0
We multiply all the terms by the denominator
40x+30x-14*50x^2=0
We add all the numbers together, and all the variables
70x-14*50x^2=0
Wy multiply elements
-700x^2+70x=0
a = -700; b = 70; c = 0;
Δ = b2-4ac
Δ = 702-4·(-700)·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-70}{2*-700}=\frac{-140}{-1400} =1/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+70}{2*-700}=\frac{0}{-1400} =0 $
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