6(3-6r)=-18+4r

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Solution for 6(3-6r)=-18+4r equation: 



6(3-6r)=-18+4r

We move all terms to the left:

6(3-6r)-(-18+4r)=0

We add all the numbers together, and all the variables

6(-6r+3)-(4r-18)=0

We multiply parentheses

-36r-(4r-18)+18=0

We get rid of parentheses

-36r-4r+18+18=0

We add all the numbers together, and all the variables

-40r+36=0

We move all terms containing r to the left, all other terms to the right

-40r=-36

r=-36/-40

r=9/10

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