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180=(2x+45)(x)
We move all terms to the left:
180-((2x+45)(x))=0
We calculate terms in parentheses: -((2x+45)x), so:We get rid of parentheses
(2x+45)x
We multiply parentheses
2x^2+45x
Back to the equation:
-(2x^2+45x)
-2x^2-45x+180=0
a = -2; b = -45; c = +180;
Δ = b2-4ac
Δ = -452-4·(-2)·180
Δ = 3465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3465}=\sqrt{9*385}=\sqrt{9}*\sqrt{385}=3\sqrt{385}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-3\sqrt{385}}{2*-2}=\frac{45-3\sqrt{385}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+3\sqrt{385}}{2*-2}=\frac{45+3\sqrt{385}}{-4} $
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