18+3x=3(2x+4)18+3x=3(2x+4)

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Solution for 18+3x=3(2x+4)18+3x=3(2x+4) equation: 



18+3x=3(2x+4)18+3x=3(2x+4)

We move all terms to the left:

18+3x-(3(2x+4)18+3x)=0



We calculate terms in parentheses: -(3(2x+4)18+3x), so:

3(2x+4)18+3x

We add all the numbers together, and all the variables

3x+3(2x+4)18

We multiply parentheses

3x+108x+216

We add all the numbers together, and all the variables

111x+216

Back to the equation:

-(111x+216)



We get rid of parentheses

3x-111x-216+18=0

We add all the numbers together, and all the variables

-108x-198=0

We move all terms containing x to the left, all other terms to the right

-108x=198

x=198/-108

x=-1+5/6

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