2(-4z-1)=3(z+2)

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Solution for 2(-4z-1)=3(z+2) equation: 



2(-4z-1)=3(z+2)

We move all terms to the left:

2(-4z-1)-(3(z+2))=0

We multiply parentheses

-8z-(3(z+2))-2=0



We calculate terms in parentheses: -(3(z+2)), so:

3(z+2)

We multiply parentheses

3z+6

Back to the equation:

-(3z+6)



We get rid of parentheses

-8z-3z-6-2=0

We add all the numbers together, and all the variables

-11z-8=0

We move all terms containing z to the left, all other terms to the right

-11z=8

z=8/-11

z=-8/11

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