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180-x=3x(90-x)
We move all terms to the left:
180-x-(3x(90-x))=0
We add all the numbers together, and all the variables
-x-(3x(-1x+90))+180=0
We add all the numbers together, and all the variables
-1x-(3x(-1x+90))+180=0
We calculate terms in parentheses: -(3x(-1x+90)), so:We get rid of parentheses
3x(-1x+90)
We multiply parentheses
-3x^2+270x
Back to the equation:
-(-3x^2+270x)
3x^2-270x-1x+180=0
We add all the numbers together, and all the variables
3x^2-271x+180=0
a = 3; b = -271; c = +180;
Δ = b2-4ac
Δ = -2712-4·3·180
Δ = 71281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-271)-\sqrt{71281}}{2*3}=\frac{271-\sqrt{71281}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-271)+\sqrt{71281}}{2*3}=\frac{271+\sqrt{71281}}{6} $
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