X2+36x-36=0

Solution for X2+36x-36=0 equation:

X2+36X-36=0

We add all the numbers together, and all the variables

X^2+36X-36=0

a = 1; b = 36; c = -36;
Δ = b2-4ac
Δ = 362-4·1·(-36)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{10}}{2*1}=\frac{-36-12\sqrt{10}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{10}}{2*1}=\frac{-36+12\sqrt{10}}{2}
$