3+3(k+2)=6(1-2)

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Solution for 3+3(k+2)=6(1-2) equation: 



3+3(k+2)=6(1-2)

We move all terms to the left:

3+3(k+2)-(6(1-2))=0

We add all the numbers together, and all the variables

3(k+2)+3-(6(-1))=0

We add all the numbers together, and all the variables

3(k+2)+9=0

We multiply parentheses

3k+6+9=0

We add all the numbers together, and all the variables

3k+15=0

We move all terms containing k to the left, all other terms to the right

3k=-15

k=-15/3

k=-5

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